打印可以相加得到给定和的元素

Input : N=5   Enter any 5 values : 3 1 6 5 7   Enter sum you want to check : 10Output : 3 1 6

STARTSTEP1-> Take values from the userSTEP2-> Take the sum a user want to check in the set.STEP3-> For i = 0; i < n; i++STEP4-> Check If sum - *(ptr+i) >= 0 then,   STEP4.1-> sum -= *(ptr+i);   STEP4.2-> Print the value of *(ptr+i)END IfEND ForSTOP

#include <stdio.h>int main(int argc, char const *argv[]){   int *ptr, n, i, sum;   printf("Enter number of digits you want to enter");   scanf("%d", &n);   ptr = (int*)malloc(sizeof(int)*n); //Dynamically allocating the memory of int   type   printf("Enter %d elements", n);   for(i = 0; i < n; i++) {      scanf("%d", (ptr+i)); //Inputting the value in dynamically      //allocated array   }   printf("Enter the sum you want to check");   scanf("%d", &sum);   for ( i = 0; i < n; i++) {      if(sum - *(ptr+i) >= 0) { //Checking the values which can be added to form the sum         X         sum -= *(ptr+i); //Updating the value of sum         printf("%d ", *(ptr+i)); //Printing the Values which can be summed up to form sum      }   }   return 0;}

Enter number of digits you want to enter5Enter 5 elements31657Enter the sum you want to check103 1 6