Python判断某个用户对某个文件的权限

百变鹏仔 3小时前 #Python

文章标签权限

在Python我们要判断一个文件对当前用户有没有读、写、执行权限，我们通常可以使用os.access函数来实现，比如：

# 判断读权限os.access(<my file>, os.R_OK)# 判断写权限os.access(<my file>, os.W_OK)# 判断执行权限os.access(<my file>, os.X_OK)# 判断读、写、执行权限os.access(<my file>, os.R_OK | os.W_OK | os.X_OK)</my></my></my></my>

但是如果要判断任意一个指定的用户对某个文件是否有读、写、执行权限，python中是没有默认实现的，此时我们可以通过下面的代码断来判断

import osimport pwdimport stat def is_readable(cls, path, user):  user_info = pwd.getpwnam(user)  uid = user_info.pw_uid  gid = user_info.pw_gid  s = os.stat(path)  mode = s[stat.ST_MODE]  return (    ((s[stat.ST_UID] == uid) and (mode &amp; stat.S_IRUSR &gt; 0)) or    ((s[stat.ST_GID] == gid) and (mode &amp; stat.S_IRGRP &gt; 0)) or    (mode &amp; stat.S_IROTH &gt; 0)    )def is_writable(cls, path, user):  user_info = pwd.getpwnam(user)  uid = user_info.pw_uid  gid = user_info.pw_gid  s = os.stat(path)  mode = s[stat.ST_MODE]  return (    ((s[stat.ST_UID] == uid) and (mode &amp; stat.S_IWUSR &gt; 0)) or    ((s[stat.ST_GID] == gid) and (mode &amp; stat.S_IWGRP &gt; 0)) or    (mode &amp; stat.S_IWOTH &gt; 0)    )def is_executable(cls, path, user):  user_info = pwd.getpwnam(user)  uid = user_info.pw_uid  gid = user_info.pw_gid  s = os.stat(path)  mode = s[stat.ST_MODE]  return (    ((s[stat.ST_UID] == uid) and (mode &amp; stat.S_IXUSR &gt; 0)) or    ((s[stat.ST_GID] == gid) and (mode &amp; stat.S_IXGRP &gt; 0)) or    (mode &amp; stat.S_IXOTH &gt; 0)    )

文章推荐

Python判断某个用户对某个文件的权限

Python如何嵌入C/C++进行开发

Python爬虫实战之爬取 V2EX 网站帖子

python+django快速实现文件上传

如何利用Fabric自动化你的任务

windows下ipython的安装与使用详解