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lintcode题目记录4

百变鹏仔 3小时前 #Python
文章标签 题目

Russian Doll Envelopes

俄罗斯玩偶嵌套问题,这个是典型的dp问题···强行遍历会提示超时,然而整了好久也没整明白怎么整,网上搜了下 把问题归结为求最长递增子序列问题··然而本人愚钝还是想不明白为啥可以这样做··虽然出来的结果是对的·····

先把数据排序, 用python内建的排序函数进行排序,但是因为当x相等时,y要按从大到小拍,所以要传一个cmp进去,python3.x不支持cmp了 所以 用了一个转换,转换成key,如果直接key设置为x默认y会按从小到大拍

这样算的结果是对的·但是那个迭代的dp不是一个有效的序列···但是长度是对的···

<span style="color: #0000ff">class</span><span style="color: #000000"> Solution:    </span><span style="color: #008000">#</span><span style="color: #008000"> @param {int[][]} envelopes a number of envelopes with widths and heights</span>    <span style="color: #008000">#</span><span style="color: #008000"> @return {int} the maximum number of envelopes</span>    <span style="color: #0000ff">def</span><span style="color: #000000"> maxEnvelopes(self, envelopes):        </span><span style="color: #008000">#</span><span style="color: #008000"> Write your code here</span>        <span style="color: #0000ff">import</span><span style="color: #000000"> functools        nums </span>= sorted(envelopes,key= functools.cmp_to_key(<span style="color: #0000ff">lambda</span> x,y:x[0]-y[0] <span style="color: #0000ff">if</span> x[0] != y[0] <span style="color: #0000ff">else</span> y[1] - x[1<span style="color: #000000">]))        size </span>=<span style="color: #000000"> len(nums)        dp </span>=<span style="color: #000000"> []        </span><span style="color: #0000ff">for</span> x <span style="color: #0000ff">in</span><span style="color: #000000"> range(size):            low, high </span>= 0, len(dp) - 1            <span style="color: #0000ff">while</span> low <=<span style="color: #000000"> high:                mid </span>= (low + high)//2                <span style="color: #0000ff">if</span> dp[mid][1] < nums[x][1<span style="color: #000000">]:                    low </span>= mid + 1                <span style="color: #0000ff">else</span><span style="color: #000000">:                    high </span>= mid - 1            <span style="color: #0000ff">if</span> low <<span style="color: #000000"> len(dp):                dp[low] </span>=<span style="color: #000000"> nums[x]            </span><span style="color: #0000ff">else</span><span style="color: #000000">:                dp.append(nums[x])        </span><span style="color: #0000ff">return</span> len(dp)