利用python怎么绘制圣诞树?
利用python怎么绘制圣诞树?本篇文章就来给大家分享利用python绘制圣诞树的几种方法,并附上python圣诞树代码和运行效果图,希望对大家有帮助。
python圣诞树代码
1、简单的绘制圣诞树
新建tree1.py或者直接输入下面代码运行(推荐学习:Python视频教程)
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#声明树的高度height = 5#树的雪花数,初始为1stars = 1#以数的高度作为循环次数 for i in range(height): print((' ' * (height - i)) + ('*' * stars)) stars += 2#输出树干print((' ' * height) + '|')
2、使用turtle绘制简单圣诞树
新建tree2py,输入以下代码
#导入turtle库import turtle#设置屏幕大小screen = turtle.Screen()screen.setup(800,600)#获取画笔并设置一些属性:圆形、红色、快circle = turtle.Turtle()circle.shape('circle')circle.color('red')circle.speed('fastest')#抬起画笔circle.up()#重新获取画笔square = turtle.Turtle()#重新设置画笔属性:四方形、绿色、快square.shape('square')square.color('green')square.speed('fastest')#重新抬起画笔square.up()#跳到指定坐标位置circle.goto(0,280)#复制当前图形circle.stamp()k = 0for i in range(1, 17): y = 30*i for j in range(i-k): x = 30*j square.goto(x,-y+280) square.stamp() square.goto(-x,-y+280) square.stamp() if i % 4 == 0: x = 30*(j+1) circle.color('red') circle.goto(-x,-y+280) circle.stamp() circle.goto(x,-y+280) circle.stamp() k += 2 if i % 4 == 3: x = 30*(j+1) circle.color('yellow') circle.goto(-x,-y+280) circle.stamp() circle.goto(x,-y+280) circle.stamp()square.color('brown')for i in range(17,20): y = 30*i for j in range(3): x = 30*j square.goto(x,-y+280) square.stamp() square.goto(-x,-y+280) square.stamp()turtle.exitonclick()
运行:
关注微信公众号:php中文网课程,回复 sd 或者 圣诞 即可获取更多圣诞节特效代码!(微信扫一扫)3、使用Turtle绘制复杂圣诞树
新建tree3.py,输入以下代码
#导入所依赖的库from turtle import *import randomimport time n = 80.0#设置速度快speed("fastest")#背景颜色 海贝壳色,偏粉色screensize(bg='seashell')left(90)forward(3*n)color("orange", "yellow")begin_fill()left(126) for i in range(5): forward(n/5) right(144) forward(n/5) left(72)end_fill()right(126) color("dark green")backward(n*4.8)def tree(d, s): if d <p>运行:</p><p style="text-align: center;"><img src="https://img.php.cn/upload/image/903/427/925/1581558755216212.png" title="1581558755216212.png" alt="3.png"></p><p>推荐学习:<a href="https://www.php.cn/course/list/30.html" target="_blank">python教程</a></p>