如何在Python中根据另一个列表的值对一个列表进行排序？

# Two Listslist1 = ['BMW', 'Toyota', 'Audi', 'Tesla', 'Hyundai']list2 = [2, 5, 1, 4, 3]print("List1 = ",list1)print("List2 (indexes) = ",list2)# Sorting the List1 based on List2res = [val for (_, val) in sorted(zip(list2, list1), key=lambda x: x[0])]print("Sorted List = ",res)

List1 =  ['BMW', 'Toyota', 'Audi', 'Tesla', 'Hyundai']List2 (indexes) =  [2, 5, 1, 4, 3]Sorted List =  ['Audi', 'BMW', 'Hyundai', 'Tesla', 'Toyota']

# Two Listslist1 = ['BMW', 'Toyota', 'Audi', 'Tesla', 'Hyundai']list2 = [2, 5, 1, 4, 3]print("List1 = ",list1)print("List2 (indexes) = ",list2)# Blank dictionarynewDict = {}# Blank listoutList = []# Both the lists in our dictionary newDictnewDict = {list1[i]: list2[i] for i in range(len(list2))}# Sorting using the sorting() based on key and values# Using lambda as wells = {k: v for k, v in sorted(newDict.items(), key=lambda item: item[1])}# Element addition in the listfor i in s.keys():   outList.append(i)print("Sorted List = ",outList)

List1 =  ['BMW', 'Toyota', 'Audi', 'Tesla', 'Hyundai']List2 (indexes) =  [2, 5, 1, 4, 3]Sorted List = ['Audi', 'BMW', 'Hyundai', 'Tesla', 'Toyota']