如何将包含重复元素的集合拆分成多个无重复元素的子集？

datas = [29, 36, 37, 37, 39, 39, 955, 955, 955, 961, 961, 962, 962]elementcounts = {}# 计算每个元素出现的次数maxcount = 0for data in datas:    if data in elementcounts:        count = elementcounts[data]    else:        count = 0    elementcounts[data] = count + 1    if count + 1 > maxcount:        maxcount = count + 1# 初始化小集合sets = []for i in range(maxcount):    sets.append(set())# 将元素添加到小集合中for key in elementcounts.keys():    count = elementcounts[key]    for i in range(count):        sets[i].add(key)# 打印小集合print(sets)

[set([29, 36]), set([37, 39]), set([955]), set([961, 962])]