如何使用 reduce 函数合并数组中连续相同项，并生成包含合并后的连续项的新数组？

let arr = [    { "start": 1, "end": 2, "content": [ "a", "b", "e" ] },    { "start": 2, "end": 3, "content": [ "b", "c" ] },    { "start": 3, "end": 4, "content": [ "b", "d" ] },    { "start": 4, "end": 5, "content": [ "d" ] },    { "start": 7, "end": 8, "content": [ "b" ] },    { "start": 9, "end": 11, "content": [ "b", "c" ] }];let obj = {};let list = arr.reduce((list, item, index, arr) => {    item.content.foreach(citem => {        let i = index;        let next, cindex;        while ((next = arr[i + 1]) && arr[i].end === next.start && (cindex = next.content.indexof(citem)) >= 0) {            i++;            next.content.splice(cindex, 1);        }        let end = arr[i].end;        let key = item.start + '-' + end;        if(!obj[key]){            list.push(obj[key] = {                start: item.start,                end,                content: [citem]            });        }else{            obj[key].content.push(citem);        }    });    return list;}, []);console.log(list);

[    { "start": 1, "end": 2, "content": [ "A", "E" ] },    { "start": 1, "end": 4, "content": [ "B" ] },    { "start": 2, "end": 3, "content": [ "C" ] },    { "start": 3, "end": 5, "content": [ "D" ] },    { "start": 7, "end": 8, "content": [ "B" ] },    { "start": 9, "end": 11, "content": [ "B", "C" ] }]