PHP前端开发

日列表功能、任务

百变鹏仔 5天前 #Python
文章标签 功能

split():

split() 方法根据分隔符将字符串划分为子字符串列表。

加入():

join() 方法使用调用它的字符串作为分隔符,将可迭代的元素连接成单个字符串。

使用循环的示例:

s = "today is thursday"reverse = ""i = 0while i<len(s):    reverse = reverse + s[-(i+1)]    i+=1print(reverse)i = 0 word = ""while i<len(reverse):    if reverse[i]==' ':        print(word[::-1],end=' ')        word = ""        i+=1        continue    word = word + reverse[i]    i+=1else:    print(word[::-1])
yadsruht si yadotthursday is today

使用列表的示例:

sen = "today is thursday"l =  sen.split(" ")print(l)print(l[::-1])s = " ".join(l[::-1])print(s)
['today', 'is', 'thursday']['thursday', 'is', 'today']thursday is today

深拷贝:

python 中的深拷贝是指创建一个新对象,该对象是原始对象的完全独立副本,包括嵌套在其中的所有对象。

l1 = [10,20,30]l2 = l1print(l1)print(id(l1))print(l2)print(id(l2))l2[0] = 111print(l1)print(l2)
[10, 20, 30]127285488814912[10, 20, 30]127285488814912[111, 20, 30][111, 20, 30]

浅复制:

浅拷贝,其中新对象是原始对象的副本,但它包含对相同嵌套对象的引用。

l1 = [10,20,30]l2 = l1.copy()print(l1)print(id(l1))print(l2)print(id(l2))l2[0] = 111print(l1)print(l2)
[10, 20, 30]140500496468800[10, 20, 30]140500496470528[10, 20, 30][111, 20, 30]

字典顺序:

词典顺序是单词在词典中按字母顺序排序的方式的概括。

l1 = ['lakshmi', 'guru', 'kuhan']l2 = ['lakshmi', 'guru', 'kuhan']print(l1 == l2)print(l1 != l2)l2 = ['guru', 'lakshmi', 'kuhan']print(l1>l2) print(l1<l2)
truefalsetruefalse

示例:

l1 = [10,20,30]l2 = [5,6,7]for no in l1:    for num in l2:        print(no, num, end=' ')    print()
10 5 10 6 10 7 20 5 20 6 20 7 30 5 30 6 30 7 

如果输出附近有 20 20,则删除:

l1 = [10,20,30]l2 = [8,20,7]for no in l1:    for num in l2:        if no==num:            print("     ", end=" ")        else:            print(no, num, end=' ')    print()
10 8 10 20 10 7 20 8       20 7 30 8 30 20 30 7 

任务:
查找给定总和的对:5

l = [1,2,3,4,5,6,7,8,9,0]for i in range(len(l)):    for j in range(len(l)):        sum = l[i] + l[j]        if sum == 5:            print(l[i], l[j])
1 42 33 24 15 00 5

找到丢失的号码:

l = [10,20,30,50,60,70,80,90]i=0while i<len(l)-1:    if l[i+1]-l[i]!=10:        result=(l[i]+l[i+1])/2        print(int(result))    i+=1
40